(fof)(1) = ?
Diketahui :
_______________________________________
- f(x) = 2x² + 2
_______________________________________
Ditanya :
_______________________________________
- (fof)(1) = ?
_______________________________________
Penyelesaian :
_______________________________________
(fof)(1)
= 2(2(1)²+2)² +2
= 2(2.1+2)² + 2
= 2(2+2)² + 2
= 2(4)² + 2
= 2.16 + 2
= 32 + 2
= 34
_______________________________________
Kesimpulan :
_______________________________________
- (fof)(1) = 34
_______________________________________
Fungsi Komposisi
Fungsi komposisi: memasukkan fungsi yang satu ke suatu fungsi yang lain.
Diketahui [tex]f(x) = 2x^2 + 2 [/tex]
Maka [tex](f~ o ~ f)(1) [/tex] :
[tex](f~ o ~ f)(x) = f(f(x)) [/tex]
[tex](f~ o ~ f)(x) = 2f^2 (x) + 2 [/tex]
[tex](f~ o ~ f)(x) = 2(2x^2 + 2)^2 + 2 [/tex]
[tex](f~ o ~ f)(x) = 2(4x^4 + 8x^2 + 4) + 2 [/tex]
[tex](f~ o~ f)(x) = 8x^4 + 16x^2 + 8 + 2 [/tex]
[tex]\large \red{\sf{(f~ o ~ f)(x) = 8x^4 + 16x^2 + 10}} [/tex]
[tex]\large \red{\sf{(f~ o~ f)(1) = 8(1)^4 + 16(1)^2 + 10}} [/tex]
[tex]\large \red{\sf{(f~ o~ f)(1) = 8 + 16 + 10}} [/tex]
[tex]\large \red{\sf{(f~ o ~ f)(1) = 34}} [/tex]
[answer.2.content]
